[JavaScript] 完整的JavaScript版的信用卡校验代码 →→→→→进入此内容的聊天室

来自 , 2021-02-13, 写在 JavaScript, 查看 147 次.
URL http://www.code666.cn/view/32c47400
  1. function isValidCreditCard(type, ccnum) {
  2.    if (type == "Visa") {
  3.       // Visa: length 16, prefix 4, dashes optional.
  4.       var re = /^4\d{3}-?\d{4}-?\d{4}-?\d{4}$/;
  5.    } else if (type == "MC") {
  6.       // Mastercard: length 16, prefix 51-55, dashes optional.
  7.       var re = /^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/;
  8.    } else if (type == "Disc") {
  9.       // Discover: length 16, prefix 6011, dashes optional.
  10.       var re = /^6011-?\d{4}-?\d{4}-?\d{4}$/;
  11.    } else if (type == "AmEx") {
  12.       // American Express: length 15, prefix 34 or 37.
  13.       var re = /^3[4,7]\d{13}$/;
  14.    } else if (type == "Diners") {
  15.       // Diners: length 14, prefix 30, 36, or 38.
  16.       var re = /^3[0,6,8]\d{12}$/;
  17.    }
  18.    if (!re.test(ccnum)) return false;
  19.    // Remove all dashes for the checksum checks to eliminate negative numbers
  20.    ccnum = ccnum.split("-").join("");
  21.    // Checksum ("Mod 10")
  22.    // Add even digits in even length strings or odd digits in odd length strings.
  23.    var checksum = 0;
  24.    for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
  25.       checksum += parseInt(ccnum.charAt(i-1));
  26.    }
  27.    // Analyze odd digits in even length strings or even digits in odd length strings.
  28.    for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
  29.       var digit = parseInt(ccnum.charAt(i-1)) * 2;
  30.       if (digit < 10) { checksum += digit; } else { checksum += (digit-9); }
  31.    }
  32.    if ((checksum % 10) == 0) return true; else return false;
  33. }
  34. //javascript/7108

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