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[Java] 获取url中的相关信息 →→→→→进入此内容的聊天室

来自 , 2020-07-01, 写在 Java, 查看 135 次.
URL http://www.code666.cn/view/6f2268bd
  1. import java.net.*;
  2. import java.io.*;
  3.  
  4. public class ParseURL {
  5.     public static void main (String [] args) throws Exception {
  6.  
  7.         URL Aurl = new URL ("http://http://yuncode.net/list/java/");
  8.         URL tuto = new URL (Aurl, "tutorial.intro.html#DOWNLOADING");
  9.         System.out.println ("protocol=" + tuto.getProtocol() );
  10.         System.out.println ("host =" + tuto.getHost() );
  11.         System.out.println ("filename=" + tuto.getFile() );
  12.         System.out.println ("port=" + tuto.getPort() );
  13.         System.out.println ("ref=" + tuto.getRef() );
  14.         System.out.println ("query=" + tuto.getQuery() );
  15.         System.out.println ("path=" + tuto.getPath() );
  16.         System.out.println ("UserInfo=" + tuto.getUserInfo() );
  17.         System.out.println ("Authority=" + tuto.getAuthority() );
  18.     }
  19. }
  20.  
  21.  

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