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[Python] python将英文单词表示的数字转换成阿拉伯数字 →→→→→进入此内容的聊天室

来自 , 2019-04-20, 写在 Python, 查看 131 次.
URL http://www.code666.cn/view/fb6c4e0b
  1. import re
  2. _known = {
  3.     'zero': 0,
  4.     'one': 1,
  5.     'two': 2,
  6.     'three': 3,
  7.     'four': 4,
  8.     'five': 5,
  9.     'six': 6,
  10.     'seven': 7,
  11.     'eight': 8,
  12.     'nine': 9,
  13.     'ten': 10,
  14.     'eleven': 11,
  15.     'twelve': 12,
  16.     'thirteen': 13,
  17.     'fourteen': 14,
  18.     'fifteen': 15,
  19.     'sixteen': 16,
  20.     'seventeen': 17,
  21.     'eighteen': 18,
  22.     'nineteen': 19,
  23.     'twenty': 20,
  24.     'thirty': 30,
  25.     'forty': 40,
  26.     'fifty': 50,
  27.     'sixty': 60,
  28.     'seventy': 70,
  29.     'eighty': 80,
  30.     'ninety': 90
  31.     }
  32. def spoken_word_to_number(n):
  33.     """Assume n is a positive integer".
  34. assert _positive_integer_number('nine hundred') == 900
  35. assert spoken_word_to_number('one hundred') == 100
  36. assert spoken_word_to_number('eleven') == 11
  37. assert spoken_word_to_number('twenty two') == 22
  38. assert spoken_word_to_number('thirty-two') == 32
  39. assert spoken_word_to_number('forty two') == 42
  40. assert spoken_word_to_number('two hundred thirty two') == 232
  41. assert spoken_word_to_number('two thirty two') == 232
  42. assert spoken_word_to_number('nineteen hundred eighty nine') == 1989
  43. assert spoken_word_to_number('nineteen eighty nine') == 1989
  44. assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989
  45. assert spoken_word_to_number('nine eighty') == 980
  46. assert spoken_word_to_number('nine two') == 92 # wont be able to convert this one
  47. assert spoken_word_to_number('nine thousand nine hundred') == 9900
  48. assert spoken_word_to_number('one thousand nine hundred one') == 1901
  49. """
  50.  
  51.     n = n.lower().strip()
  52.     if n in _known:
  53.         return _known[n]
  54.     else:
  55.         inputWordArr = re.split('[ -]', n)
  56.  
  57.     assert len(inputWordArr) > 1 #all single words are known
  58.     #Check the pathological case where hundred is at the end or thousand is at end
  59.     if inputWordArr[-1] == 'hundred':
  60.         inputWordArr.append('zero')
  61.         inputWordArr.append('zero')
  62.     if inputWordArr[-1] == 'thousand':
  63.         inputWordArr.append('zero')
  64.         inputWordArr.append('zero')
  65.         inputWordArr.append('zero')
  66.     if inputWordArr[0] == 'hundred':
  67.         inputWordArr.insert(0, 'one')
  68.     if inputWordArr[0] == 'thousand':
  69.         inputWordArr.insert(0, 'one')
  70.  
  71.     inputWordArr = [word for word in inputWordArr if word not in ['and', 'minus', 'negative']]
  72.     currentPosition = 'unit'
  73.     prevPosition = None
  74.     output = 0
  75.     for word in reversed(inputWordArr):
  76.         if currentPosition == 'unit':
  77.             number = _known[word]
  78.             output += number
  79.             if number > 9:
  80.                 currentPosition = 'hundred'
  81.             else:
  82.                 currentPosition = 'ten'
  83.         elif currentPosition == 'ten':
  84.             if word != 'hundred':
  85.                 number = _known[word]
  86.                 if number < 10:
  87.                     output += number*10
  88.                 else:
  89.                     output += number
  90.             #else: nothing special
  91.             currentPosition = 'hundred'
  92.         elif currentPosition == 'hundred':
  93.             if word not in [ 'hundred', 'thousand']:
  94.                 number = _known[word]
  95.                 output += number*100
  96.                 currentPosition = 'thousand'
  97.             elif word == 'thousand':
  98.                 currentPosition = 'thousand'
  99.             else:
  100.                 currentPosition = 'hundred'
  101.         elif currentPosition == 'thousand':
  102.             assert word != 'hundred'
  103.             if word != 'thousand':
  104.                 number = _known[word]
  105.                 output += number*1000
  106.         else:
  107.             assert "Can't be here" == None
  108.  
  109.     return(output)
  110. #//python/5048

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